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Q Problem 1: A manager wants to determine the number of containers to use for incoming parts for a kanban system to be installed next month. The process will have a usage rate of 80 pieces per hour. Because the process is new, the manager has assigned an inefficiency factor of .35. Each container holds 45 pieces, and it takes an average of 75 minutes to complete a cycle. How many containers should be used? As the system improves, will more or fewer containers be required? Why? Problem 2: A JIT system uses kanban cards to authorize movement of incoming parts. In one portion of the system, a work center uses an average of 100 parts per hour while running. The manager has assigned an inefficiency factor of .20 to the center. Standard containers are designed to hold six dozen parts each. The cycle time for parts containers is about 105 minutes. How many containers are needed?

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Solution for Problem No. 1: D = Per hour 80 pieces T = 75 minutes = 1.25 hour C = 45 X = 0.35 N = ? N = [DT(1+X)]/C = [80(1.25)(1+0.35)]/45 = 3 Containers Therefore, 3 containers should be used.